A figure is composed of a semicircle and a right triangle. Determine the area of the shaded region. Use 3.14 for π and round to the nearest tenth. Show all of your work.

A figure is composed of a semicircle and a right triangle Determine the area of the shaded region Use 314 for π and round to the nearest tenth Show all of your class=

Respuesta :

Answer:

[tex]A=9.5\ ft^2[/tex]

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of triangle plus the area of semicircle

so

[tex]A=\frac{1}{2}bh+\frac{1}{2}\pi r^{2}[/tex]

we have

[tex]b=4\ ft[/tex]

Find the height of the right triangle applying the Pythagorean Theorem

[tex]5^2=h^2+4^2[/tex]

[tex]h^2=9\\h=3\ ft[/tex]

The radius of the semicircle is half the height of triangle

[tex]r=3/2=1.5\ ft[/tex]

substitute in the formula

[tex]A=\frac{1}{2}(4)(3)+\frac{1}{2}(3.14)(1.5)^{2}[/tex]

[tex]A=6+3.5=9.5\ ft^2[/tex]

The area of the figure is 9.5 square units

Area of the figure = area of the semicircle + area of triangle;

The height of the triangle is calculated as:

h^2 = 5^2 - 4^2

h = √25 - 16

h = 3

Area of the figure = π(3)²/8 + 1/2(3(4)

Area of the figure = 3.5325 + 6

Area of the figure = 9.5 square units

Learn more on area here: https://brainly.com/question/11423300