Respuesta :

SaniShahbaz

Step-by-step explanation:

Given the function

[tex]f\left(x\right)=\frac{1}{2}\cdot 2^x[/tex]

  • Putting x = -2

[tex]\frac{1}{2}\cdot \:2^{-2}=\frac{1}{2}\cdot \frac{1}{4}=\frac{1}{8}[/tex]

so

(x, f(x)) will be (-2, 1/8)

  • Putting x = -1

[tex]\frac{1}{2}\cdot \:\:2^{-1}=\frac{1}{2}\cdot \:\frac{1}{2}=\frac{1}{4}[/tex]

so

(x, f(x)) will be (-1, 1/4)

  • Putting x = 0

[tex]\frac{1}{2}\cdot \:2^0=\frac{1}{2}[/tex]

so

(x, f(x)) will be (0, 1/2)

  • Putting x = 1

[tex]\frac{1}{2}\cdot \:\:2^1=2\cdot \:\frac{1}{2}=1[/tex]

so

(x, f(x)) will be (1, 1)

  • Putting x = 2

[tex]\frac{1}{2}\cdot \:\:2^2=4\cdot \:\frac{1}{2}=2[/tex]

so

(x, f(x)) will be (2, 2)

The graph is also attached below.

Ver imagen SaniShahbaz

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