How many milliliters of a 2.00 M KBr are needed to prepare 250.0 mL of 0.60 M KBr?

Answer:
75mL
Explanation:
Data obtained from the question include:
C1 = 2M
V1 =?
C2 = 0.60M
V2 = 250mL
The original volume of solution can be obtained as follows:
C1V1 = C2V2
2 x V1 = 0.6 x 250
Divide both side by 2
V1 = (0.6 x 250) / 2
V1 = 75mL
The volume needed is 75mL