Answer:
25116 J
Explanation:
The amount of heat required to raise the temperature of a substance is given by the equation
[tex]Q=mC\Delta T[/tex]
where
m is the mass of hte substance
C is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature
For the sample of water in this problem, we have:
m = 0.20 kg is the mass
[tex]C=4186 J/kg^{\circ}C[/tex] is the specific heat of water
[tex]\Delta T=45-15=30^{\circ}C[/tex] is the increase in temperature
Therefore, the amount of heat required is
[tex]Q=(0.20)(4186)(30)=25116 J[/tex]
