Respuesta :

Eduard22sly

Answer:

The 3rd option Summation(4^i-4)

Step-by-step explanation:

Summation(4^i-4)

When i = 1

4^I-4 = 4^1-4 = 4^-3 = 1/64

When i = 2

4^i-4 = 4^2-4 = 4^-2 = 1/16

When i = 3

4^i-4 = 4^3-4 = 4^-1 = 1/4

When i = 4

4^i-4 = 4^4-4 = 4^0 = 1

When i = 5

4^i-4 = 4^5-4 = 4^1 = 4

nightstarshooter

Answer:

[tex]\sum _{i=1}^54^{i-4}[/tex]

Step-by-step explanation:

[tex]a_{1} \\[/tex] = First term

In this case, our first term is [tex]\frac{1}{64}[/tex]

The ratio of all of the adjacent terms is 4

[tex]a_{1} \\[/tex] = [tex]4^1^-^4[/tex]

[tex]a_{1}=\frac{1}{64}[/tex]

~Hope this helps!~

Otras preguntas