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If it takes 43.32ml of .1M NaOH to neutralize a 50ml HCL solution, how many moles of NaOH were added to the HCL solution?

Respuesta :

Answer:

4.332 millimoles of NaOH

Explanation:

Molarity (M) = moles per liter (mole/L); liters x moles/liter = moles

0.04332 L x 0.1 mole/liter = 0.004332 moles of NaOH (4.332 millimoles)

millimoles / milliliters = moles/liter = molarity (M).

4.332 millimoles / 50 milliliters = 0.08664 M HCl

In the Volumetric titration at the end point, moles of NaOH = moles of HCl

NaOH + HCl --> H2O + NaCl

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