Answer:
Answer is no. I give you a defined explanations.
The given number cannot be a square number.
Step-by-step explanation:
The given number is 3481_62_728
[tex]observing \: the \: single \: digit \: square \: pattern \\ 1 {}^{2} = 1 \\ 2 { }^{2} = 4 \\ 3 {}^{2} = 9 \\ 4 {}^{2} = 16 \\ 5 {}^{2} = 25 \\ 6 {}^{2} = 36 \\ 7 {}^{2} = 49 \\ 8 {}^{2} = 64 \\ 9 {}^{2} = 81 \\ and \: 10 {}^{2} = 100 \\ this \: pattern \: show \: that \: all \: the \: square \: numbers \\ end \: with \: 1, 4 ,9 ,6 \: ,5 \:, again6 \: ,9 \: ,4, \: 1and \: 0 \\ here \: the \: given \: number \: end \: with \: 8 \\ no \: square \: number \: whose \: end \: digit \: is \: 8[/tex]
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