Answer:
The SIMD only gets the effect of 5.3 processors from 10 processors while the MIMD only gets the effect of 6.9 processors out of 10 processors.
Explanation:
According to Amdahl's law for an SIMD machine, the fraction parallel work is 90% while the fraction of serial work is 10% for a time [tex]T_{10} =0.1[/tex], [tex]T_{1}+0.9[/tex], [tex]\frac{T _{1}}{10}[/tex]
The speedup = [tex]\frac{T_{1}}{(0.1+\frac{0.9}{10})T_{1} }=\frac{1}{0.19} =5.26[/tex]
for an MIMD machine, the fraction parallel work is 95%, since vectorized work can also be paralleled by multiple processors, the time for 10 processors is
[tex]T_{10} =0.05[/tex], [tex]T_{1}+0.95[/tex], [tex]\frac{T _{1}}{10}[/tex]
The speedup = [tex]\frac{T_{1}}{(0.05+\frac{0.95}{10})T_{1} }=\frac{1}{0.145} =6.9[/tex]
The SIMD only gets the effect of 5.3 processors from 10 processors while the MIMD only gets the effect of 6.9 processors out of 10 processors.
