The height of the given trapezoid is 7.5 m.
Step-by-step explanation:
Step 1:
The trapezoid's area is calculated by averaging the base lengths and multiplying it with the trapezoid's height.
The trapezoid's area, [tex]A = \frac{b_{1}+b_{2}}{2} (h).[/tex]
Here [tex]b_{1}[/tex] is the lower base length and [tex]b_{2}[/tex] is the upper base length while h is the height.
Step 2:
In the given problem, [tex]b_{1}=5 \mathrm{m}[/tex] and [tex]b_{2}=3 \mathrm{m}[/tex]. Assume the height is h m.
The trapezoid's area [tex]= 30.[/tex]
[tex]30 = \frac{5+3}{2} (h), 30 = (4)(h).[/tex]
[tex]h = \frac{30}{4} = 7.5.[/tex]
So the height of the given trapezoid is 7.5 m.
