Answer:
The vapor pressure for a mist is [tex]P= 25.92\ Torr[/tex]
Explanation:
From the question we are given that
The radius is [tex]r = 3.70 *10^{-8} m[/tex]
The temperature is [tex]T = 298K[/tex]
The vapor pressure of water [tex]P_o = 25.2\ Torr[/tex]
The density of water is [tex]\rho = 998 kg.m^{-3}[/tex]
The surface tension of water is [tex]\sigma = 71.99 m N \cdot m^{-1}[/tex]
Generally the equation of that is mathematically represented as
[tex]ln (\frac{P}{P_0} ) = \frac{2 \sigma M}{r \rho RT}[/tex]
Where P is the vapor pressure for mist
R is the ideal gas constant = 8.31
making P the subject in the formula
[tex]P = e^ {\frac{2 \sigma M}{r \rho RT}} * P_0[/tex]
[tex]= e^{\frac{2 *(0.07199)(0.018)}{(3.70*10^{-8})(998)(8.31)(298)} } * 25.2[/tex]
[tex]P= 25.92Torr[/tex]
