Answer:
The magnetic flux links to its turns = [tex]7.6 \times10^{-3}[/tex] Wb.
Explanation:
Given :
Radius of circular coil = [tex]18 \times 10^{-2}[/tex] m
Number of turns = 25
Magnetic field = [tex]3 \times10^{-3}[/tex] T
Magnetic flux (Φ) is a measure of the magnetic field lines passes through a given area. The unit of magnetic flux is weber (Wb).
We know that,
⇒ Φ = [tex]BA[/tex]
Where [tex]B =[/tex] ext. magnetic field, [tex]A =[/tex] area of loop or coil.
But here given in question, we have turns of wire so our above eq. modified as follows.
⇒ Φ = [tex]NBA[/tex]
Where [tex]N =[/tex] no. of turns.
∴ Φ = [tex]25 \times 3 \times 10^{-3} \pi (18 \times10^{-2} )^{2}[/tex]
Φ = [tex]7.6 \times 10^{-3} Wb[/tex]
Thus, the magnetic flux links to its turns = [tex]7.6 \times 10^{-3} Wb[/tex]
