Answer:
[tex]10\sqrt 2 iN[/tex] and [tex]10\sqrt 2 jN[/tex]
Step-by-step explanation:
We are given that
Force =F=20 N
[tex]\theta=\frac{\pi}{4}[/tex]
We have to find the horizontal and vertical component of the force.
Horizontal component of the force =[tex]F_x=Fcos\theta i[/tex]
Horizontal component of the force=[tex]F_x=20cos\frac{\pi}{4}i=10\sqrt 2 iN[/tex]
Vertical component of the force,[tex]F_y=Fsin\theta j[/tex]
Vertical component of the force,[tex]F_y=20sin\frac{\pi}{4}j=10\sqrt 2 jN[/tex]
Force,[tex]F=F_x+F_y[/tex]
[tex]F=10\sqrt 2i N+10\sqrt 2j N[/tex]
