Answer:
123 J transfer into the gas
Explanation:
Here we know that 123 J work is done by the gas on its surrounding
So here gas is doing work against external forces
Now for cyclic process we know that
[tex]\Delta U = 0[/tex]
so from 1st law of thermodynamics we have
[tex]dQ = W + \Delta U[/tex]
[tex]dQ = W[/tex]
so work done is same as the heat supplied to the system
So correct answer is
123 J transfer into the gas