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A tuning fork vibrating at 512 Hz is held near one end of a tube of length that is open at both ends, as shown above. The column of air in the tube resonates at its fundamental frequency. The speed of sound in air is 340 m/s. Calculate the length of the tube.

Respuesta :

Answer:

Length of the pipe is 33.2 cm

Explanation:

As we know that the frequency of the sound in open end pipe is given as

[tex]f = \frac{v}{2L}[/tex]

so here we will have

f = 512 Hz

v = 340 m/s

so now we have

[tex]512 = \frac{340}{2L}[/tex]

[tex]L = \frac{170}{512}[/tex]

[tex]L = 33.2 cm[/tex]

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