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A resistor is made out of a long wire having a length LLL. Each end of the wire is attached to a terminal of a battery providing a constant voltage VVV0. A current III flows through the wire. If the wire were cut in half, making two wires of length LLL/2, and both wires were attached to the battery (the end of both wires attached to one terminal, and the other ends attached to the other terminal), what would be the total current flowing through the two wires?

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Answer:

Explanation:

length of the wire = L

Potential difference = Vo

Current = I

new length of the wire, L' = L/2

As we know that the resistance of the wire is directly proportional to the length of the wire.

As the length is halved so that the resistance is also halved.

Resistance = Voltage / Current

V = I R

So, Voltage is constant and the resistance is halved so that the current is doubled.

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