If you shine a laser on two slits with a separation of 0.215 mm, and the diffraction pattern shines on a background 4.90 m away, what is the wavelength of the laser light if the fringes are separated by 1.60 cm

Respuesta :

Answer:

[tex]\lambda = 702\ nm[/tex]

Explanation:

Given,

slit width, d = 0.215 mm

slit separation, D = 4.90 m

Wavelength of the laser light = ?

Fringe width.[tex]\beta = 1.60\ cm[/tex]

Using formula

[tex]\beta =\dfrac{\lambda D}{d}[/tex]

[tex]\lambda=\dfrac{\beta d}{D}[/tex]

[tex]\lambda=\dfrac{0.016\times 0.215\times 10^{-3}}{4.90}[/tex]

[tex]\lambda = 7.02\times 10^{-9}\ m[/tex]

[tex]\lambda = 702\ nm[/tex]

Wavelength of the laser light = [tex]\lambda = 702\ nm[/tex]