Incomplete question.Here is complete question
Two long, parallel wires are separated by 2.0 m. Each wire has a 30-A current, but the currents are in opposite directions.(a) Determine the magnitude of the net magnetic field midway between the wires.(b) Determine the magnitude of the net magnetic field at a point 1.3 m to the side of one wire and 3.9 m from the other wire. The point is in the same plane as the wires. Express your answer with the appropriate units.
Answer:
[tex](a) B=12*10^{-6}T\\\\\\(b)B_{net}=3.1*10^{-6}T[/tex]
Explanation:
Given data
[tex]d_{wire}=2.0m\\I_{1,2}=30A[/tex]
The current flow in wire is opposite
The direction of magnetic field is the same between two wires
For Part (a)
[tex]B=2*u\frac{I}{2\pi r}\\ B=2*(4\pi *10^{-7})\frac{30}{2\pi (\frac{2}{2} )} \\B=12*10^{-6}T[/tex]
For Part (b)
The magnetic field at this point will be sum of the magnetic field of each wire
[tex]B_{1}=u\frac{I}{2\pi r} \\B_{1}=(4\pi *10^{-7})\frac{30}{2\pi (1.3)}\\ B_{1}=4.615*10^{-6}T\\\\\\B_{2}=u\frac{I}{2\pi r}\\B_{2}=(4\pi *10^{-7})\frac{30}{2\pi (3.9)}\\B_{2}=1.5385*10^{-6}T\\\\B_{net}=B_{1}-B_{2}\\B_{net}=4.615*10^{-6}T-1.5385*10^{-6}T\\B_{net}=3.1*10^{-6}T[/tex]
