An unknown weak acid, HA, it titrated with 1.2 M NaOH. The pH at the halfway point of this titration was found to be 4.081. If the initial pH of the weak acid solution (before titration) has a pH of 2.348, what was the concentration of the weak acid solution

Respuesta :

Answer: The initial concentration of weak acid solution is 0.243 M

Explanation:

We are given:

pH of unknown acid at the halfway point of titration = 4.081

We know that:

[tex]pH=pK_a=4.081[/tex]     (At halfway point)

To calculate the [tex]K_a[/tex], we use the equation:

[tex]pK_a=-\log (K_a)[/tex]

Putting values in above equation, we get:

[tex]4.081=-\log (K_a)\\\\K_a=10^{-4.081}=8.298\times 10^{-5}[/tex]

As, the initial pH of the acid is 2.348

  • To calculate the hydrogen ion concentration, we use the equation:

[tex]pH=-\log [H^+][/tex]

Putting values in above equation, we get:

[tex]2.348=-\log [H^+][/tex]

[tex][H^+]=10^{-2.348}=4.487\times 10^{-3}[/tex]

The chemical equation for the ionization of weak acid follows:

[tex]HA\rightleftharpoons H^++A^-[/tex]

The expression of [tex]K_a[/tex] for above equation:

[tex]K_a=\frac{[H^+][A^-]}{[HA]}[/tex]

As, [tex][H^+]=[A^-]=4.487\times 10^{-3}[/tex]

Putting values in above equation, we get:

[tex]8.298\times 10^{-5}=\frac{(4.487\times 10^{-3})\times (4.487\times 10^{-3})}{[HA]}[/tex]

[tex][HA]=0.243M[/tex]

Hence. the initial concentration of weak acid solution is 0.243 M