The length of CD is 12 units C’D’ is the image of CD under a dilation with a scale factor of n.Which of these are true?

Answer: FIrst option, Fourth option and Fifth option.
Step-by-step explanation:
First it is important to know the definition of "Dilation".
A Dilation is defined as a transformation in which the Image (which is the figure obtained after the transformation) and the Pre-Image (this is the original figure, before the transformations) have the same shape, but their sizes are different.
If the length of CD is dilated with a scale factor of "n" and it is centered at the origin, the length C'D' will be:
[tex]C'D'=nCD=(n)(12\ units)[/tex]
Therefore, knowing this, you can determine that:
1. If [tex]n=\frac{3}{2}[/tex] , you get:
[tex]C'D'=(\frac{3}{2})(12\ units)=18\ units[/tex]
2. If [tex]n=4[/tex], then the length of C'D' is:
[tex]C'D'=(4)(12\ units)=48\ units[/tex]
3. If [tex]n=8[/tex], then:
[tex]C'D'=(8)(12\ units)=96\ units[/tex]
4. If [tex]n=2[/tex], then, you get that the lenght of C'D' is:
[tex]C'D'=(2)(12\ units)=24\ units[/tex]
5. If [tex]n=\frac{3}{4}[/tex], the length of C'D' is the following:
[tex]C'D'=(\frac{3}{4})(12\ units)=9\ units[/tex]
Answer: 1, 3, and 4 are correct
Step-by-step explanation: 1. 3/2 = 1.5 1.5 x 12 =18 3. 12 x 2 = 24 4. 3/4= 0.75 0.75 x 12 = 9
The rest are incorrect