A buffer solution is composed of 4.00 4.00 mol of acid and 3.25 3.25 mol of the conjugate base. If the p K a pKa of the acid is 4.70 4.70 , what is the pH of the buffer?

Respuesta :

Answer: The pH of the buffer is 4.61

Explanation:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

[tex]pH=pK_a+\log(\frac{[\text{conjuagate base}]}{[\text{acid}]})[/tex]

We are given:

[tex]pK_a[/tex] = negative logarithm of acid dissociation constant of weak acid = 4.70

[tex][\text{conjuagate base}]}[/tex] = moles of conjugate base = 3.25 moles

[tex][\text{acid}][/tex]  = Moles of acid = 4.00 moles

pH = ?

Putting values in above equation, we get:

[tex]pH=4.70+\log(\frac{3.25}{4.00})\\\\pH=4.61[/tex]

Hence, the pH of the buffer is 4.61