Answer:
Explanation:
The power rating is 5W
And resistance is 14kΩ=14000
Given that,
Power in an electric circuit is
P=i^2×R
Therefore,
5=i^2× 14000
divide both side by 14000
i^2=5/14000
i^2=0.0003571
Then take square of both side
i=0.019amps
Then the maximum current it can hold without damage is 0.019amps