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A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that μs = 0.50 and μk = 0.30 between the belt and the computer. How far is the computer dragged before it is riding smoothly on the belt?

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usmanbiu

Answer:

x = 1.63 m

Explanation:

mass (m) = 10 kg

μk = 0.3

velocity (v) = 3.1 m/s

Assuming that most of the computers weight is applied on the belt instantaneously, we can apply the constant acceleration equation below

x = [tex]v^{2}/2a[/tex]

where a = μk.g , therefore

x = [tex]v^{2}[/tex]/2μk.g

x = (3.1 x 3.1)/(2 x 0.3 x 9.8)

x = 1.63 m

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