Respuesta :
Answer:
[tex] 76 W *\frac{1kW}{1000 W}= 0.076 kW[/tex]
[tex] 0.076 kW * 6.3 \frac{hours}{day}= 0.4788 \frac{kWh}{day}[/tex]
[tex] 113x10^6 people * \frac{0.4788 kWh}{people}= 54104400 kWh[/tex]
And finally we can convert this into money like this:
[tex]54104400 kWh *\frac{0.089 dollars}{1 kWh}= 4815291.6[/tex]
So they spent every day approximately in total $ 4815291.6 dollars
Step-by-step explanation:
For this case we can convert the average power into Kw like this:
[tex] 76 W *\frac{1kW}{1000 W}= 0.076 kW[/tex]
Now on average we know that one person use on average this power over 6.3 hours per day so then we have the following consumption rate:
[tex] 0.076 kW * 6.3 \frac{hours}{day}= 0.4788 \frac{kWh}{day}[/tex]
And now we know the total population so then the total consumption per day would be:
[tex] 113x10^6 people * \frac{0.4788 kWh}{people}= 54104400 kWh[/tex]
And finally we can convert this into money like this:
[tex]54104400 kWh *\frac{0.089 dollars}{1 kWh}= 4815291.6[/tex]
So they spent every day approximately in total $ 4815291.6 dollars
Answer:
A = $4,815,291.6 approximately $4.8 million
The total amount used to keep 113 million TV turned on per day in the United States is $4,815,291.6
Step-by-step explanation:
Given;
Number of TVs in the United States N = 113 million
Average power per TV P = 76 W
Average TV use per day t = 6.3 hours a day
Cost rate of electrical energy R = 0.089 dollars per kWh
The total amount used to keep 113 million TV turned on is;
A = Total Energy consumption × cost rate
A = Et × R
Total Energy consumption of 113 million TVs with 76W at 6.3 hours a day is
Et = NPt = 113 million × 76 × 6.3 = 54.1044millon kWh
From
A = Et × R
A = 54.1044millon kWh × 0.089 dollars/kWh
A = 4.8152916 million dollars
A = $4.815 million or $4,815,291.6
