Answer:
The vacationer's average density is 912 kg/m³
Explanation:
Archimedes principle states that the buoyancy of an object in a liquid is equal to the weight of the liquid displaced, hence since we have
Density of sea water = 1025 kg/m³
Volume of vocationer's body below water = 89 % of total volume
Mass of seawater displaced = mass of vocationer
volume of seawater displaced = 0.89 × volume of vocationer
volume of vocationer = (volume of seawater displaced)/0.89
Density of vocationer = mass/volume = (mass of seawater displaced)×0.89/(volume of seawater displaced)
Therefore deensity of vocationer = 0.89×density of seawater
= 1025×0.89 = 912 kg/m³