Respuesta :
Answer:
The percentage of ice berg under water is 92%
Step-by-step explanation:
From Archimede's Principle, we know that the Buoyant Force is equal to the weight of fluid displaced. Hence, the mass of fluid (water) displaced, will be equal to the weight of the object in vacuum.
Therefore,
(Density of Water)(Volume of Ice Berg inside Water) = (Density of Ice Berg)(Total Volume of Ice Berg)
(Volume of Ice Berg inside Water)/(Total Volume of Ice Berg) = (Density of Ice Berg)/(Density of water)
(Volume of Ice Berg inside Water)/(Total Volume of Ice Berg) = % of Ice Berg Under Water = (0.92 g/cm³)/(1.0 g/cm³) * 100%
% of Ice Berg Under Water = 92%
The percentage of iceberg underwater is 92%
The calculation is as follows:
According to Archimede's Principle, Buoyant Force should be equivalent to the weight of the fluid displaced.
So,
Percentage of Ice Berg Under Water = [tex](0.92 g/cm^3)\div (1.0 g/cm^3) \times 100\%[/tex]
= 92%
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