Answer:
The electric flux through surface 1 is greater than the electric flux through surface 2.
Step-by-step explanation:
Electric Flux is given as:
Φ = E*A
where E = Electric field
A = surface area.
For surface 1,
Φ(1) = E(1)*A(1)
For surface 2,
Φ(2) = E(2)*A(2)
Since both surfaces have the same charge, the electric fields will be the same.
Hence, E(1) = E(2) = E
From the question we are given that:
A(1) = 0.5A(2)
Hence,
Φ(1) = E*A(1)
Φ(2) = E*A(2) = E*0.5A(1)
Φ(2) = 0.5E*A(1)
Comparing Φ(1) and Φ(2), we see that Φ(1) is 2 time greater than Φ(2), hence, the Flux through surface 1 is greater than the Flux through surface 2.
