Answer: Molarity of this solution is 0.88 M
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
Given : 3.0 g of hydrogen peroxide is present in 100 g of solution.
n = moles of solute = [tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{3.0g}{34g/mol}=0.088mol[/tex]
[tex]V_s[/tex] = volume of solution in ml= [tex]\frac{\text {mass of solutuion}}{\text {density of solution}}=\frac{100g}{1.01g/ml}=99.0ml[/tex]
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.088moles\times 1000}{99.0ml}=0.88mole/L[/tex]
Thus molarity of this solution is 0.88 M
