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if 5.50 mol of calcium carbide (CaC 2 ) reacts with an excess of water, how many moles of acetylene (C 2 H 2 ) , a gas used in welding , will be produced? CaC2(s)+2H2O(l) Ca(OH) 2 (aq)+C2H2 (g)

Respuesta :

Eduard22sly

Answer:

5.5moles

Explanation:

CaC2 + 2H2O —> Ca(OH)2 + C2H2

From the equation, the following were observed:

1mole of CaC2 reacted to produced 1mol of C2H2.

Therefore, 5.5moles of CaC2 will also produce 5.5moles of C2H2

The moles of acetylene produced in the reaction of 5.5 mol calcium carbide has been 5.5 mol.

The stoichiometric coefficient in the balanced chemical equation has been equivalent to the moles of each reactant required to form the product.

Computation for moles of Acetylene produced:

From the balanced chemical equation of formation of acetylene, 1 mole of Calcium carbide is required for producing 1 mole of acetylene.

From the balanced equation:

[tex]\rm 1\;mol\;CaC_2=1\;mol\;C_2H_2[/tex]

The available moles of calcium carbide has been 5.5 mol. The moles of acetylene produced has been:

[tex]\rm 1\;mol\;CaC_2=1\;mol\;C_2H_2\\5.5\;mol\;CaC_2=5.5\;mol\;C_2H_2[/tex]

The moles of acetylene produced in the reaction of 5.5 mol calcium carbide has been 5.5 mol.

For more information about moles produced, refer to the link:

https://brainly.com/question/10606802

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