Answer:
T = 5.635 Nm
Explanation:
Parameters given:
Mass of rod, m = 1kg
Length of rod, L = 1m
Mass of sphere, M = 0.5kg
Radius of sphere, R = 30 cm = 0.3m
Angle, θ = 30°
Torque is given as:
T = rFsinθ
F represents force. The force acting on both the rod and the sphere is their individual weights. Weight acts at the Centre of a body.
Because the system is made of two parts, the rod and the sphere, we add the individual torque of both parts:
T = mg(L/2)sinθ + Mg(L + R)sinθ
Where g = acceleration due to gravity.
T = ( 1 * 9.8 * 1 * 0.5) sin30 + (0.5 * 9.8 * (1 + 0.3)) sin30
T = (4.9*0.5) + (6.37*0.5)
T = 2.45 + 3.185
T = 5.635 Nm
