Respuesta :
Answer:
The molality of the solution is 1.94molal
Explanation:
The molality of a solution is defined as
[tex]m=\frac{Solute(mol)}{Solvent(Kg)}[/tex]
Using the Molarity we find that
[tex]M=\frac{solute(mol)}{VolumeOfSolution(L)}[/tex]
We know that in 1,0L of solution there are 1,80mol of HNO3
[tex]Solute(mol)=(1,00L)(1,80M)\\\\Solute(mol)=1,80mol[/tex]
Now, we know that
[tex]Mass of solvent(g) = Mass of solution(g) - Mass of solute(g)\\\\Mass of water(g)= Mass of solution(g) - Mass of HNO3(g)\\\\[/tex]
Using the density of the solution, we find the mass of it
[tex]Mass of solution(g) = Density(g/mL). Volume(mL)\\\\Mass of solution(g) = (1,04g/mL)(1000mL)\\\\Mass of solution(g) = 1040g = 1,04Kg[/tex]
Now, we calculate the mass of HNO3
[tex]Mass of HNO3(g) = (number of moles) (Molecular Weight)\\\\Mass of HNO3 (g) = (1,80mol)(63,015g/mol) = 113,43g\\\\Mass of HNO3(Kg)= 0,113Kg\\[/tex]
Now we find the mass of the water (solvent) and proceed to calculate the molality
[tex]Mass of water(Kg) = 1,040Kg - 0,113Kg = 0,927Kg\\\\m=\frac{1,80mo}{0,927Kg}=1,94molal[/tex]
