Explanation:
The given data is as follows.
Q = 620 C, t = 0.510 hour
First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.
[tex]0.510 hr \times \frac{3600 sec}{1 hr}[/tex]
= 1836 sec
Therefore, we will calculate the average current as follows.
I = [tex]\frac{Q}{t}[/tex]
= [tex]\frac{620 C}{1836 sec}[/tex]
= 0.337 C/sec
It is known that,
1 C/sec = 1000 mA
So, [tex]0.337 C/sec \times \frac{1000 mA}{1 C/s}[/tex]
= 337 mA
Thus, we can conclude that the average current in milliamperes is 337 mA.
