Surface area of the cylinder = 816.4 sq. ft.
Solution:
Height of the cylinder = 21 ft
Diameter of the cylinder = 10 ft
Radius of the cylinder = 10 ÷ 2 = 5 ft
Use the value of [tex]\pi[/tex] = 3.14
Surface area of the cylinder = [tex]2 \pi r h+2 \pi r^{2}[/tex]
Substitute the given values in the surface area formula, we get
Surface area of the cylinder [tex]$=2\times3.14\times 5\times 21+2 \times3.14\times 5^2[/tex]
[tex]=659.4+157[/tex]
[tex]=816.4[/tex] ft²
Hence the surface area of the cylinder is 816.4 sq. ft.
