Answer:
marginal revenue is -6
and production levels 200, 50
Explanation:
given data
R(x) = 10 x - 0.04 x²
solution
we have given
R(x) = 10 x - 0.04 x²
so here R'(x) is
R'(x) = 10(1) - 0.4 (2x)
R'(x) = 10 - 0.8 x ....................1
so here at x is 20 marginal revenue will be
R'(20) = 10 - 0.8(20)
R'(20) = 10 - 16
R'(20) = - 6
and
when revenue is $400
R(x) = 400
400 = 10 x - 0.04 x²
x= 200, 50