Answer: The net charge on the sphere is -5.9nC
Explanation:
The electric field outside the conducting solid sphere is given as:
E = (kq)/r^2
Here, q is the net charge on the sphere and r is the distance from the center of the sphere.
The net charge is calculated as follows;
q = Er^2/k
E = 2.7*10^3N/C
r = 14cm = 0.14m
k = 8.99*10^9Nm^2/C^2
q = (2.7*10^3)(0.14^2)/(8.99*10^9)
q = 5.9*10^-9C
= 5.9nC
As the electric field directed radially inward, the net charge on the sphere is negative.
Hence the net charge on the sphere is -5.9nC
Answer:
The net charge on the sphere is - 5.9 × 10⁻⁹ C = - 5.9 nC
Explanation:
The electric field (E) produced by a charge of magnitude Q, at a point with distance r away from the charge, is given by
E = kQ/r²
where k = Coulomb's constant = 9.0 x 10⁹ Nm²/C²
The electric field 14 cm (0.14 m) from the sphere is 2.7 × 10³ N/C
2.7 × 10³ = 9.0 x 10⁹ × Q/(0.14²)
Q = (2.7 × 10³ × 0.14²)/(9.0 x 10⁹) = 5.9 × 10⁻⁹ C
Since the charge is directed inwards towards the centre of the sphere, the sign on it will be -ve. Q = - 5.9 × 10⁻⁹ C
b) The electric field 9 cm (0.09 m) from the sphere will be
E = kQ/(0.09²) = (9 × 10⁹ × 5.9 × 10⁻⁹)/(0.09²) = 6555.56 = 6.56 × 10³ N/C
