Answer: The concentration of hydrogen ions is [tex]4.7\times 10^{-4}M[/tex]
Explanation:
We are given:
Concentration of acid = 0.22 M
The chemical equation for the dissociation of monoprotic weak acid follows:
[tex]HA\rightleftharpoons H^++A^-[/tex]
Initial: 0.22
At eqllm: 0.22-x x x
The expression of [tex]K_a[/tex] for the above equation follows:
[tex]K_a=\frac{[H^+][A^-]}{[HA]}[/tex]
We are given:
[tex]K_a=1.0\times 10^{-6}[/tex]
Putting values in above equation, we get:
[tex]1.0\times 10^{-6}=\frac{x\times x}{(0.22-x)}\\\\x=-0.00047,0.00047[/tex]
Neglecting the negative value of 'x', because concentration cannot be negative
So, equilibrium concentration of hydrogen ions = x = 0.00047 M = [tex]4.7\times 10^{-4}M[/tex]
Hence, the concentration of hydrogen ions is [tex]4.7\times 10^{-4}M[/tex]
