Answer:
[tex]V(0)=15.4\\V(3)=0.1\\V(6)=-15.2[/tex]
Step-by-step explanation:
The potential in a region between x = 0 and x = 6.00 m is V = a + bx.
Put a = 15.4 V and b = -5.10 V/m.
So, [tex]V=15.4-5.10x[/tex]
To find: Potential at x =0, 3, 6
Solution:
Potential at x = 0:
[tex]V=15.4-0=15.4[/tex]
Potential at x = 3:
[tex]V=15.4-5.10(3)=15.4-15.3=0.1[/tex]
Potential at x = 6:
[tex]V=15.4-5.10(6)=15.4-30.60=-15.2[/tex]
Therefore,
[tex]V(0)=15.4\\V(3)=0.1\\V(6)=-15.2[/tex]