70-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 844 N. What is the acceleration of the elevator?

Respuesta :

Answer : The acceleration of the elevator is, [tex]2.25m/s^2[/tex]

Explanation :

Formula used to calculate the acceleration of the elevator is:

[tex]F=mg+ma\\\\ma=F-mg\\\\a=\frac{F-mg}{m}[/tex]

where,

F = force = 844 M

m = mass of man = 70 kg

g = acceleration due to gravity = [tex]9.8m/s^2[/tex]

a = acceleration of the elevator = ?

Now put all the given values in the above formula, we get:

[tex]a=\frac{F-mg}{m}[/tex]

[tex]a=\frac{844N-(70kg\times 9.8m/s^2)}{70kg}[/tex]

[tex]a=2.25m/s^2[/tex]

Thus, the acceleration of the elevator is, [tex]2.25m/s^2[/tex]