Help please
Find the equation of a line that joins the midpoint of (7, 3) and (9, -7) and the y-intercept of
5x – 6 = 2y.​

Help pleaseFind the equation of a line that joins the midpoint of 7 3 and 9 7 and the yintercept of5x 6 2y class=

Respuesta :

Answer:

y = [tex]\frac{1}{8}[/tex] x - 3

Step-by-step explanation:

Use the midpoint formula

Given (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ [tex]\frac{1}{2}[/tex] (x₁ + x₂ ), [tex]\frac{1}{2}[/tex] (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (7, 3) and (x₂, y₂ ) = (9, - 7), thus

midpoint = [ [tex]\frac{1}{2}[/tex] (7 + 9), [tex]\frac{1}{2}[/tex] (3 - 7 ) ] = (8, - 2)

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The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 5x - 6 = 2y into this form by dividing all terms by 2

y = [tex]\frac{5}{2}[/tex] x - 3 ← in slope- intercept form

with y- intercept c = - 3 ⇒ (0, - 3 )

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Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂, x₁ )

with (x₁, y₁ ) = (8, - 2) and (x₂, y₂ ) = (0, - 3)

m = [tex]\frac{-3+2}{0-8}[/tex] = [tex]\frac{-1}{-8}[/tex] = [tex]\frac{1}{8}[/tex]

y = [tex]\frac{1}{8}[/tex] x - 3 ← equation of line