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Consider two air-filled parallel-plate capacitors with circular plates. Capacitor 1 has a distance between plates d and plate radius R. Capacitor 2 has a distance between plates 2d and plate radius R/2.
If the capacitance of capacitor 1 is C, then the capacitance of capacitor 2 is?

Respuesta :

Answer:

1/8 x C

Explanation:

The capacitance of parallel plate capacitor

= ε₀ A /d where A is area of plate and d is distance between plate.

for capacitor 1

C =  ε₀ A /d

For capacitor 2

radius = R/2

Area = A / 4

Capacitance

= ε₀ (A/4) x ( 1 / 2d )

= ( 1 / 8) x (ε₀ A /d)

= 1/8 x C

The capacitance of capacitor 2 is 1/8 x C

calculation of capacitor 2:

The capacitance of parallel plate capacitor

= ε₀ A /d

where A is area of plate

and d is distance between plate.

So,

for capacitor 1

C =  ε₀ A /d

And

For capacitor 2

radius = R/2

Area = A / 4

Now

Capacitance

= ε₀ (A/4) x ( 1 / 2d )

= ( 1 / 8) x (ε₀ A /d)

= 1/8 x C

learn more about the radius here: https://brainly.com/question/18648019

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