Imagine two doors 1 meter apart on a wall. How fast does an average person (84 kg) have to walk to be able to go through both doors simultaneously? (Hint: diffraction will be observed when the wavelength is comparable to the slit separation) O 8 x 10-36 m s1 O 8 x 1036 ms1 O impossible to calculate O 100 ms1

Respuesta :

Answer:

The velocity of average person is [tex]8\times10^{-36}\ m/s[/tex]

(1) is correct option.

Explanation:

Given that,

Wavelength = 1 m

Mass of average person = 84 kg

We need to calculate the velocity of average person

Using De Broglie wavelength

[tex]\lambda=\dfrac{h}{mv}[/tex]

[tex]v=\dfrac{h}{m\lmbda}[/tex]

Where, [tex]\lambda[/tex] = wavelength

h = plank constant

m = mass

v = velocity

Put the velocity into the formula

[tex]v=\dfrac{6.626\times10^{-34}}{84\times1}[/tex]

[tex]v=8\times10^{-36}\ m/s[/tex]

Hence, The velocity of average person is [tex]8\times10^{-36}\ m/s[/tex]