Answer:
The electrostatic force away from the negative charge is [tex]9\times10^{8}\ N[/tex]
(b) is correct option.
Explanation:
Given that,
First charge = 5.0 C
Second charge = -2.0 C
Distance = 10 m
We need to calculate the electrostatic force on the positive charge
Using formula of electrostatic force
[tex]F=\dfrac{kq_{1}q_{2}}{r^2}[/tex]
Where, q₁ = first charge
q₂= second charge
r = distance
Put the value into the formula
[tex]F_{12}=\dfrac{9\times10^{9}\times5.0\times(-2.0)}{10^2}[/tex]
[tex]F_{12}=−900000000\ N[/tex]
[tex]F_{12}=-9\times10^{8}\ N[/tex]
The electrostatic force away from the negative charge.
Hence, The electrostatic force away from the negative charge is [tex]9\times10^{8}\ N[/tex]
