An advertiser goes to a printer and is charged $48 for 50 copies of one flyer and $66 for 197 copies of another flyer. The printer charges a fixed setup cost plus a charge for every copy of the flyer. Find a function that describes the cost of a printing job, if n is the number of copies made

Respuesta :

Answer:

Step-by-step explanation:

Let n represent the number of copies made.

Let y represent the cost of making n copies.

If we plot y on the vertical axis and n on the horizontal axis, a straight line would be formed. The slope of the straight line would be

Slope, m = (66 - 48)/(197 - 50)

m = 18/147 = 0.122

The equation of the straight line can be represented in the slope-intercept form, y = mx + c

Where

c = intercept

m = slope

To determine the intercept, we would substitute x = 66, y = 48 and m = 0.122 into y = mx + c. It becomes

48 = 0.122 × 66 + c = 8.052 + c

c = 48 - 8.052

c = 39.948

The linear function that describes the cost of a printing job would be

y = 0.122n + 39.948

Answer:

[tex]C(n) = \dfrac{6156}{147} + \dfrac{18}{147}(n)[/tex]

where n is the number of flyers.                                

Step-by-step explanation:

we are given the following in the question:

Let x be the fixed cost and y be the variable cost for every flyer in dollars.

Cost of 50 copies = $48

Thus, we can write he equation:

[tex]x + 50y = 48[/tex]

Cost of 197 copies = $66

Thus, we can write the equation:

[tex]x + 197y = 66[/tex]

Solving the two equation by elimination, we get,

[tex]x + 197y - (x + 50y) = 66-48\\(197-50)y = 18\\147y = 18\\y = \dfrac{18}{147}\\\\x = 48 - \dfrac{18}{147}(50)\\\\x = \dfrac{6156}{147}[/tex]

Thus, we can write the cost function as:

[tex]C(n) = \dfrac{6156}{147} + \dfrac{18}{147}(n)[/tex]

where n is the number of flyers.