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Among 27 external speakers, there are three defectives. An inspector examines 7 of these speakers.
Find the probability that there are at least 2 defective speakers among the 7
(round off to second decimal place).

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Answer:

SDCSSC S CD  DS D SDC SD CSD CDS S SA D SADS S  E FD F DD VDF V DFV DF V DFV DFV DS V DSVD V SD DS SD CDS C DV DF V DFV DF V DFV DF VDFV DFVD VDF V DFV D VDV DFV DFV DF

Step-by-step explanation:

VDFV D VDV D VDF D V  VFV DF VD   DF V D VFD

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The probability of randomly selecting atleast 2 defective speakers from 7 trials is 0.18

The probability of randomly selecting a defective speaker can be calculated thus :

  • P(defective) = number of defective speakers / total speakers

  • P(defective) = 3 / 27 = 0.1111

Using the binomial probability relation :

  • P(x = x) = nCx * p^x * q^(n-x)
  • Probability of success, p = 0.1111
  • n = number of trials = 7
  • x ≥ 2
  • q = 1 - p = 1 - 0.1111 = 0.889

P(x ≥ 2 ) = P(x = 2)+P(x = 3)+P(x = 4)+P(x = 5)+P(x =6)+P(x = 7)

Using a binomial probability calculator to save time :

P(x ≥ 2 ) = 0.17785

P(x ≥ 2 ) = 0.18 ( 2 decimal places)

Therefore, the probability of selecting atleast 2 defective speakers from 7 is 0.18

Learn more : https://brainly.com/question/12474772

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