Answer:
This is the correct question.
Apply the junction rule to the junction labeled with the number1 (at the bottom of the resistor of resistance R_2).
Answer in terms of given quantities,together with the meter readings I_1 and I_2 and the current I_3.
b) Apply the loop rule to loop 2 (the smaller loop on the right).Sum the voltage changes across each circuit element around this loop going in the direction of the arrow. Remember that the current meter is ideal.
Express the voltage drops in terms ofV_b, I_2, I_3, the given resistances, and any other givenquantities.
c) Now apply the loop rule to loop 1(the larger loop spanning the entire circuit). Sum the voltagechanges across each circuit element around this loop going in thedirection of the arrow.
Express the voltage drops in terms ofV_b, I_1, I_3, the given resistances, and any other givenquantities.
Explanation:
a. Junction rule: Kirchhoff current law (KCL)
Then, total current entering a junction equals to current leaving the junction.
Therefore,
i1=i2+i3
b. Apply Kirchoff voltage law ( KVL) to loop 2
Then, sum of voltage in the loop equals to zero.
-i3R3+i2R2=0.
Then,
i2R2=i3R3
c. Apply KVL to the loop 1
-Vb+i1R1+i3R3
Therefore,
Vb=i1R1+i3R3.
The circuit diagram is in the attachment
