Respuesta :
Answer:
0.211 kg
Explanation:
specific heat capacity of copper = 385 J/Kgk
heat loss by copper = mcθ = 3.8 × (8 - 84 ) × 385 = - 111188 J
heat needed to raise the temperature of water from 0°C to 8°C
= mcθ = 1.2 kg × 4180 × ( 8 - 0) = 40128 J
111188 J - 40128 J = 71060
71060 = ml
71060 / 336000 = mass of ice where latent heat of fusion = 3.36 × 10⁵JKg⁻¹
m = 0.211 kg
Answer:
0.215 kg of ice
Explanation:
Mass of copper, m = 3.8 kg
Specific heat of Copper, Cp = 385 J/kg•K;
Change in temperature = 84 - 8
= 76°C
q = m* Cp * delta T
= 385 * 3.8 * 76
= 111188 J
111188 J = 26.575 kcal
The energy needed to heat 1.2 kg of water from 0°C to 8°C = q
q = m * Cp * delta T
= (1.2 kg)(1 kcal/kg•°C)(8°C)
= 9.6 kcal
Therefore,
delta q = q1 - q2
= 26.575 - 9.6
= 16.975 kcal were used to melt the ice.
Energy needed to melt ice at 0°C = 79 kcal/kg
Mass = 16.975/79
= 0.215 kg of ice.
14 kcal/(79 kcal/kg) = 0.18 kg.
