A spherical mirror is polished on both sides. When the concave side is used as a mirror, the magnification is 4.4. What is the magnification when the convex side is used as a mirror, the object remaining the same distance from the mirror?

Respuesta :

Answer:

[tex]m = \frac{-4.4}{7.4}[/tex]

Explanation:

magnification is the ratio of distance of image to distance of object

i.e. [tex]m = -\frac{d_i}{d_o}[/tex]

[tex]d_i = -4.4 d_o[/tex]

As per the lens equation,

[tex]\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f}[/tex]

We will calculate the focal length of the mirror

[tex]\frac{1}{yd_o} + \frac{1}{-4.4d_o} = \frac{1}{f} \\\frac{4.4 -1}{4.4} \frac{1}{d_o} = \frac{1}{f}\\f = \frac{4.4}{3.4} d_o[/tex]

Now for convex mirror only the sign will change

Thus, focal length would be equal to

[tex]f = - \frac{4.4}{3.4} d_o[/tex]

Plugging this value into lens equation, we get

[tex]\frac{1}{d_o} + \frac{1}{d_i} = \frac{1}{f} \\\frac{1}{d_o} + \frac{1}{d_i} = \frac{-3.4}{4.4} \frac{1}{d_o} \\\frac{7.4}{4.4} \frac{1}{d_o} = \frac{1}{d_i}\\\frac{d_i}{d_o} = \frac{4.4}{7.4} \\m =- \frac{d_i}{d_o} \\\\m = - \frac{4.4}{7.4}[/tex]