Answer:
Horizontal Distance d=2.14 m
Explanation:
Given data
Mass m=15.0 g =0.015 kg
Height h=1.21 m
Angle α=31.0°
To find
Horizontal distance d
Solution
The horizontal distance as given as:
[tex]d_{distance}=((vi_{initail-velocity})^{2} /g_{gravity} )*Sin2\alpha[/tex]
First We need to find the initial velocity Vi
So
[tex]v_{i}=\sqrt{2gh}\\v_{i}=\sqrt{2(9.8m/s)(1.21m)}\\v_{i}=4.87m/s[/tex]
Substitute the given values and initial velocity to find horizontal distance:
So
[tex]d=(vi^{2} /g)*Sin2\alpha\\ d=(\frac{(4.87m/s)^{2} }{9.8m/s^{2} } )Sin(2*31.0)\\d=2.14m[/tex]
