Answer:
D, A & B, C, E
Explanation:
In each problem, sum the torques about the edge of the table.
A) ∑τ = Iα
mg (-1.5 m) + (100 kg) g (1.5 m) = 0
m = 100 kg
B) ∑τ = Iα
mg (-0.75 m) + (100 kg) g (0.75 m) = 0
m = 100 kg
C) ∑τ = Iα
mg (-1.5 m) + (100 kg) g (0.75 m) = 0
m = 50 kg
D) ∑τ = Iα
mg (-1.5 m) + (200 kg) g (1.5 m) = 0
m = 200 kg
E) ∑τ = Iα
mg (-1.5 m) + (100 kg) g (0.5 m) = 0
m = 33.3 kg