Answer:
49.52 g of H₂O
Explanation:
The balance chemical equation for given reaction is as follow;
4 HCl + O₂ → 2 H₂O + 2 Cl₂
Step 1: Find out Limiting reagent as;
According to balance equation,
4 moles of HCl reacted with = 1 mole of O₂
So,
5.50 moles of HCl will react with = X moles of O₂
Solving for X,
X = 5.50 mol × 1 mol / 4 mol
X = 1.375 moles of O₂
This means to completely consume 5.5 moles of HCl we will need 1.375 moles of O₂ while, we are provided with 3.0 moles of O₂ which is in excess hence, the limiting reagent in this problem is HCl and it will control the yield of products.
Step 2: Calculate Moles of H₂O produced;
According to balance equation,
4 moles of HCl produced = 2 moles of H₂O
So,
5.50 moles of HCl will react with = X moles of H₂O
Solving for X,
X = 5.50 mol × 2 mol / 4 mol
X = 2.75 moles of H₂O
Step 3: Calculate Mass of H₂O as;
Mass = Moles × M.Mass
Mass = 2.75 mol × 18.01 g/mol
Mass = 49.52 g of H₂O
