Respuesta :
Answer:
Bus B travel faster
Step-by-step explanation:
The graph of the question in the attached figure
we know that
the linear equation in slope intercept form is equal to
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-intercept
x ---> is the time in hours
y ---> is the distance in miles
In this problem we have
Bus A
[tex]y=\frac{125}{5}x[/tex]
The slope of the linear equation represent the speed of the bus
so
The speed of bus A is
[tex]\frac{125}{5}=25\ miles/hour[/tex]
Bus B
Find the slope
take two points from the graph
(0,0) and (3,200)
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
substitute
[tex]m=\frac{200-0}{3-0}[/tex]
[tex]m=66.67\ \frac{miles}{hour}[/tex]
Compare the slope Bus A with the slope Bus B
[tex]66.67\ \frac{miles}{hour} > 25\ \frac{miles}{hour}[/tex]
therefore
Bus B travel faster

some of the equations are not couply able so here u go
The graph of the question in the attached figure
we know that
the linear equation in slope intercept form is equal to
y = mx + b
where
m is the slope
b is the y-intercept
x --> is the time in hours
y --> is the distance in miles
In this problem we have
Bus A
y = 125/5 x
The slope of the linear equation represent the speed of the bus
so
The speed of bus A is
125/5 = 25 miles/hour
Bus B
Find the slope
take two points from the graph
(0,0) and (3,200)
The formula to calculate the slope between two points is equal to
m = y2 + y1/x2 - x1
substitute
m = 200 - 0/3 - 0
m = 66.67 miles/hour
Compare the slope Bus A with the slope Bus B
66.67 mile/hour > 25 miles /hour
therefore
Bus B travel faster