Bus A travels according to the function y = 125/5x where y is distance traveled in miles and x is time in hours. Bus B travels according to the graph below, where the distance y is a function of time x. Which bus travels faster? Include all necessary calculations in your final answer.


Respuesta :

Answer:

Bus B travel faster

Step-by-step explanation:

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope

b is the y-intercept

x ---> is the time in hours

y ---> is the distance in miles

In this problem we have

Bus A

[tex]y=\frac{125}{5}x[/tex]

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

[tex]\frac{125}{5}=25\ miles/hour[/tex]

Bus B

Find  the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

substitute

[tex]m=\frac{200-0}{3-0}[/tex]

[tex]m=66.67\ \frac{miles}{hour}[/tex]

Compare the slope Bus A with the slope Bus B

[tex]66.67\ \frac{miles}{hour} > 25\ \frac{miles}{hour}[/tex]

therefore

Bus B travel faster

Ver imagen calculista

some of the equations are not couply able so here u go

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

y = mx + b

where

m is the slope

b is the y-intercept

x --> is the time in hours

y --> is the distance in miles

In this problem we have

Bus A

y = 125/5 x  

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

125/5 = 25 miles/hour

Bus B

Find  the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

m = y2 + y1/x2 - x1

substitute

m = 200 - 0/3 - 0  

m = 66.67 miles/hour

Compare the slope Bus A with the slope Bus B

66.67 mile/hour > 25 miles /hour

therefore

Bus B travel faster